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3x^2+7x-216=0
a = 3; b = 7; c = -216;
Δ = b2-4ac
Δ = 72-4·3·(-216)
Δ = 2641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{2641}}{2*3}=\frac{-7-\sqrt{2641}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{2641}}{2*3}=\frac{-7+\sqrt{2641}}{6} $
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